2x(3x-4)=2(3x^2+8)

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Solution for 2x(3x-4)=2(3x^2+8) equation: 


Simplifying
2x(3x + -4) = 2(3x2 + 8)

Reorder the terms:
2x(-4 + 3x) = 2(3x2 + 8)
(-4 * 2x + 3x * 2x) = 2(3x2 + 8)
(-8x + 6x2) = 2(3x2 + 8)

Reorder the terms:
-8x + 6x2 = 2(8 + 3x2)
-8x + 6x2 = (8 * 2 + 3x2 * 2)
-8x + 6x2 = (16 + 6x2)

Add '-6x2' to each side of the equation.
-8x + 6x2 + -6x2 = 16 + 6x2 + -6x2

Combine like terms: 6x2 + -6x2 = 0
-8x + 0 = 16 + 6x2 + -6x2
-8x = 16 + 6x2 + -6x2

Combine like terms: 6x2 + -6x2 = 0
-8x = 16 + 0
-8x = 16

Solving
-8x = 16

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Divide each side by '-8'.
x = -2

Simplifying
x = -2

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